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14d^2-37d=0
a = 14; b = -37; c = 0;
Δ = b2-4ac
Δ = -372-4·14·0
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-37}{2*14}=\frac{0}{28} =0 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+37}{2*14}=\frac{74}{28} =2+9/14 $
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